q=%28%E7%BE%8E%29%E7%BA%A6%E7%BF%B0+S.+%E5%93%88%E8%92%99%E5%BE%B7%28John+S.+Hammond%29%EF%BC%8C%2C%E7%8E%8B%E6%AD%A3%E6%9E%97%E8%AF%91&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
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(美)约翰 S. 哈蒙德(John S. Hammond),,王正林译